# WHAT DOES HCL + BA(OH)2 EQUAL?

a) Calculate the heat (in kJ) released (make sure to lớn use the correct sign in your answer) when 106.7 mL of 0.365 M HCl is mixed with excess Ba(OH)2.

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b) How many grams of barium hydroxide are required to produce enough energy khổng lồ heat a 509.8 g of sample of water from 22.3°C to 96.6°C? a) mol HCl = 0.1067 L x 0.365 mol/L = 0.03895 moles

∆H = 0.03895 mol HCl x -118 kJ/2 mol HCl = -2.30 kJ

b) First, we"ll find the heat needed lớn heat 509.8 g of water from 22.3 to lớn 96.6 degrees

q = mC∆T

q = (509.8 g)(4.184 J/gº)(74.3º) = 158,482 J = 158.5 kJ This is the heat needed

From the equation for the reaction of Ba(OH)2 & HCl, we see that reaction of 1 mol Ba(OH)2 will generate 118 kJ of heat. From this info, we can determine moles Ba(OH)2 needed to generate 158.5 kJ.

158.5 kJ x 1 mol Ba(OH)2 / 118 kJ = 1.35 moles Ba(OH)2 needed

Converting this to grams, we have...

1.35 mol Ba(OH)2 x 171.3 g/mol = 231 g Ba(OH)2 needed

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